- The % by mass of the elements in a compound is called the percent composition
How to find the percent composition: 1. Calculate molar mass
2. Calculate each element percentage of that total
Give percentage to 1decimal place
-Percent composition tells what part of a compound each component makes up
Ex1. What is the % composition of CO2?
1 mole C= 1×12.0= 12.0g
2mole O= 2 ×16.0= 32.0g
44.0g
%C= (mass of carbon)/(mass of CO2)=(12.0×100%)/44.0g=27.3%
%O= (mass of oxygen)/(mass of CO2)= (32.0×100%)/44.0g=72.7%
%C= (mass of carbon)/(mass of CO2)=(12.0×100%)/44.0g=27.3%
%O= (mass of oxygen)/(mass of CO2)= (32.0×100%)/44.0g=72.7%
Check to see if the result is close to 100%:27.3%+72.7%= 100%
Because of rounding answer may also be shown as 99.9 and 100.1 which are both OK
Ex2. What is the % composition of the entire element in glucose: C6H12O6
C = 72.0g H=12.0g O= 96.0g Total Mass=180.0g
%C= (72.0g×100%)/180.0g= 40.0%
%H= (12.0g×100%)/180.0g= 6.7%
%O= (96.0g×100%)/180.0g= 53.3%
40.0+6.7+53.3=100%
%H= (12.0g×100%)/180.0g= 6.7%
%O= (96.0g×100%)/180.0g= 53.3%
40.0+6.7+53.3=100%
To find the percent composition of a group of atoms (Al2(SO4)3), the total of the mass of the group atom is used for the percentage
Ex3. Find the % SO4 in Al2(SO4)4
2Al× 27.0g= 54g
3S × 32.1g= 96.3g 96.3(Sulphur)+192.0(Oxygen)=288.3g
12O× 16.0g= 192.0g
342.3g
%SO4= 288.3g/342.3×100%= 84.2%SO4
From the percent composition, ratio of moles can be determined and this will result in an empirical formula
From the percent composition, ratio of moles can be determined and this will result in an empirical formula
Step 1: Assume 100.0g of material
Step 2: Convert all %s to grams Step 3: Convert grams to moles
Step 4: divide all moles by the smallest; this will give you a ratio to determine the empirical formula
Ex4. Sample of compound: 45.8% Sulphur and 54.2% Flouride. Give the empirical formula
Step 1: Assume the 100.0g of material
Step 2: Therefore: 45.8g S and 54.2g F
Step 3: 45.8/32.1g= 1.4268molS 54.2/19.0g= 2.8526molF
Step 4: 2.8526/1.4268= 1.99993/(1moleS)= SF2
Therefore the empirical formula for 45.8% Sulphur and 54.2% Flouride is SF2
How to calculate percent composition1: V=xbEeyT8nK84
How to calculate percent composition2: V=_H009sTvYE0
Therefore the empirical formula for 45.8% Sulphur and 54.2% Flouride is SF2
How to calculate percent composition1: V=xbEeyT8nK84
How to calculate percent composition2: V=_H009sTvYE0


